Question

efectuați: (2^10-2^9)*(2^9-2^8)*(2^8-2^7):2^24.​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns: $\bf \red{\underline{~1~}}$

Explicație pas cu pas:

$\bf \big(2^{10}-2^9\big)\cdot \big(2^9-2^8\big)\cdot \big(2^8-2^7\big):2^{24}=$

$\bf 2^9\cdot\big(2^{10-9}-2^{9-9}\big)\cdot 2^8\cdot \big(2^{9-8}-2^{8-8}\big)\cdot 2^7\cdot \big(2^{8-7}-2^{7-7}\big):2^{24}=$

$\bf 2^9\cdot\big(2^{1}-2^{0}\big)\cdot 2^8\cdot \big(2^{1}-2^{0}\big)\cdot 2^7\cdot \big(2^{1}-2^{0}\big):2^{24}=$

$\bf 2^9\cdot\big(2-1\big)\cdot 2^8\cdot \big(2-1\big)\cdot 2^7\cdot \big(2-1\big):2^{24}=$

$\bf 2^9\cdot1\cdot 2^8\cdot 1\cdot 2^7\cdot 1:2^{24}=$

$\bf 2^{9+8+7}:2^{24}= 2^{24}:2^{24}= 2^{24-24}=2^{0}=\red{\underline{~1~}}$

$\pink{\bf \star~\underline{Formule~pentru~puteri}:}$

$\bf a^{0} = 1;$

$\bf (a^{n})^{m} = a^{n \cdot m};$

$\bf a^{n}\cdot a^{m} =a^{n+m};$

$\bf a^{n}: a^{m} =a^{n-m}$

==pav38==

Baftă multă !