Question

efectuati:
(256:2+1):3x2-[(64:2+21x3)+1]:3=?
6000-{125+[300:100x8+(21x3+63)]}=?
3+2x{51-50:[700-(600+11x5)]-40}=?
va rog ajutaatima

Answer 1

(256:2+1):3x2-[(64:2+21x3)+1]:3=
(128+1):3x2-(32+63+1):3=
129:3*2-96:3=
43*2-32=
86-32=
54

6000-{125+[300:100x8+(21x3+63)]}=
6000-[125+(3x8+63+63)]=
6000-(125+24+126)=
6000 - 275=
5725

3+2x{51-50:[700-(600+11x5)-40]}=
3+2x{51-50:[700-(600+55)-40]}=
3+2x[51-50:(700-655-40)]=
3+2x[51-50:(45-40)]=
3+2x(51-50:5)=
3+2x(51-10)=
3+2x41=
3+82=
85