Question

Efectuati:[3^12×(-9^5)×(-28)^2]^2÷(9^3)^9.Raspuns: 3^2=9​

Answer 1

[3^12*(-9)^5*(-27)^2]^2:(9^3)^9

[3^12*(-3^2)^5*27^2]^2:9^27

(3^12*3^10*27^2)^2:(3^2)^27

[3^22*(3^3)^2)^2:3^54

(3^22*3^6)^2:3^54

(3^28)^2:3^54

3^56:3^54

3^2

9