Question

Efectuați :[3,2+2,5*(10-8,9)-0,19*5]^2*(6,25-1,5^2)

B). [(3,16-1,15-0,1^2):0,5^2+0,02:0,01]:2,5^2

Pls :) ​

Answer 1

Răspuns:

$\color{red}\Large \boxed{\bf 100}$

$\color{blue}\Large \boxed{\bf 1,6}$

Explicație pas cu pas:

$\large \bf a)~~[3,2+2,5\cdot(10-8,9)-0,19\cdot5]^{2}\cdot(6,25-1,5^{2}) =$

$\large \bf (3,2+2,5\cdot 1,1-0,95)^{2}\cdot(6,25-2,25) =$

$\large \bf (3,2+2,75-0,95)^{2}\cdot 4 =$

$\large \bf (5,95-0,95)^{2}\cdot 4 =$

$\large \bf 5^{2}\cdot 4 =$

$\large \bf 25\cdot 4 =$

$\color{red}\large \boxed{\bf 100}$

$\large \bf b)~~[(3,16-1,15-0,1^{2}):0,5^{2}+0,02:0,01]:2,5^{2}=$

$\large \bf [(3,16-1,15-0,01):0,25+2]:6,25=$

$\large \bf [(2,01-0,01):0,25+2]:6,25=$

$\large \bf (2:0,25+2):6,25=$

$\large \bf (8+2):6,25=$

$\large \bf 10:6,25=$

$\color{blue}\large \boxed{\bf 1,6}$

#copaceibrainly