Question

Efectuati:(3+3^2):2^2-2017^0+1^2016..Repede va rog!!!

Answer 1

(3+3^2):2^2-2017^0+1^2016

(3+3^2):2^2-1+1^2017

(3+3^2):2^2-1+1

(3+9):2^2-1+1

(3+9):2^2

12:2^2

12 supra 2^2

12 supra 4 = 3

Raspunsul este 3.