Question

Efectuati 5/x-2y-3/x+2y ; x-1/2x-6+1/3-x ; 5/x²-16-7/x-4

Answer 1

$\frac{5}{x-2y} - \frac{3}{x+2y} = \frac{5(x+2y)-3(x-2y)}{(x-2y)(x+2y)} = \frac{2x+16y}{ x^{2} -4 y^{2} }$

$\frac{5}{ x^{2}-16 } - \frac{7}{x-4} = \frac{5-7(x+4)}{ x^{2} -16} = \frac{-23-7x}{ x^{2}-16 }$