Question

Efectuati:(6a^2bc^2 supra -4ab^3):(9a^3c^2 supra -2b^3c):(-5ac supra 2b.Va rogg repede

Answer 1

Răspuns:

Explicație pas cu pas:

$\frac{6a^{2}bc^{2}}{-4ab^{3}}:\frac{9a^{3}c^{2}}{-2b^{3}c}:\frac{-5ac}{2b}=\frac{3ac^{2}}{-2b^{2}}:\frac{9a^{3}c}{-2b^{3}}:\frac{-5ac}{2b}=\frac{3ac^{2}}{-2b^{2}}*\frac{-2b^{3}}{9a^{3}c} *\frac{2b}{-5ac}=\frac{3*(-2)*2*ab^{4}c^{2}}{-2*9*(-5)*a^{4}b^{2}c^{2}}=-\frac{2b^{2}}{15a^{3}}$