Question

efectuati: 8+2×[2^6:4^2+2^3:(16^2:8^2-64:2^5)]
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Answer 1

$8 + 2 \times ( {2}^{6} \div {4}^{2} + {2}^{3} \div ( {16}^{2} \div {8}^{2} - 64 \div {2}^{5})) =$