Question

efectuati: 85 supra 800:[1 supra 19*(1supra20+ 1supra 40+1 supra 50)+ 1 supra 360:(1 supra 30-1 supra 45)]

Answer 1

17/160:[1/19*(10/200+5/200+4/200)+1/360:(3/90-2/90)]= 17/160:[1/19*(10+5+4)/200+1/360:(3-2)/90]= 17/160:(1/19*19/200+1/360:1/90) =17/160:(1/200+1/360*90/1)= 17/160:(1/200+1/4)= 17/160:(1/200+50/200)= 17/160: (1+50)/200=17/160:51/200=
17/160*200/51=1/4*5/3= 5/(4*3) =5/12.

Answer 2

85 /800:[1 /19*(1/20+ 1/ 40+1 / 50)+ 1 /360:(1/ 30-1 / 45)]=
85 /800:[1 /19*(10/200+ 5/ 200+4/ 200)+ 1 /360:(3/ 90-2 / 90)]=
85 /800:(1 /19*19/200+ 1 /360:1/ 90)=
85 /800:(1 /200+ 1/4)=
85 /800:(1 /200+ 50/200)=
85/800:51/200=
85/800*200/51=
85/4*1/51=
85/204=
0,41(6)