Question

Efectuati:
a) 0,35+0,49=
b)9,7+41,3=
c)3,994+9,273=
d)17,83+0,529=
e)0,347+15=
f)9+29,8=
g)17+3,225=
h)234+0,234=
i)0,(5)+0,(4)=
j)0,(35)+0,(13)=
k)0,(7)+0,(51)=
l)0,(75)+2,(5)
m)12,3(4)+0,5(6)=
n)2,5(15)+3,(21)=
o)0,(135)+0,(531)=
p)3,2+1 supra 5=
r)7,35+ 1 supra 8+2,(3)=
s)0,45+2,(3)+3,(15)+5,55=
Multumesc

Answer 1

$a).0,35+0,49=0,84 \\ \\ b).9,7+41,3=51 \\ \\ c).3,994+9,273=13,267 \\ \\ d).17,83+0,529=18,359 \\ \\ e).0,347+15=15,347 \\ \\ f).9+29,8=38,8 \\ \\ g).17+3,225=20,225 \\ \\ h).234+0,234=234,234$

$i).0,(5)+0,(4)= \frac{5}{9} + \frac{4}{9} = \frac{9}{9} =1 \\ \\ j).0,(35)+0,(13)= \frac{35}{99} + \frac{13}{99} = \frac{48}{99} = \frac{16}{33} \\ \\ k).0,(7)+0,(51)= \frac{7}{9} + \frac{51}{99} = \frac{693}{891} + \frac{459}{891} = \frac{1152}{891} = \frac{128}{99} \\ \\ l).0,(75)+2,(5)= \frac{75}{99} + \frac{23}{9} = \frac{675}{891} + \frac{2277}{891}= \frac{2952}{891} = \frac{328}{99}$

$m).12,3(4)+0,5(6)= \frac{1111}{90} + \frac{51}{90} = \frac{1162}{90} = \frac{581}{45} \\ \\ n).2,5(15)+3,(21)= \frac{2490}{990} + \frac{318}{99} = \frac{2490}{990} + \frac{3180}{990} = \frac{5670}{990} = \frac{63}{11} \\ \\ o).0,(135)+0,(531)= \frac{135}{999} + \frac{531}{999} = \frac{666}{999} = \frac{6}{9} = \frac{2}{3} \\ \\ p).3,2+ \frac{1}{5} =3,2+0,2=3,4$

$q).7,35+ \frac{1}{8} +2,(3)= \frac{735}{100} + \frac{1}{8} + \frac{21}{9} = \frac{13230}{1800} + \frac{225}{1800} + \frac{4200}{1800} = \frac{17655}{1800} \\ \\ r).0,45+2,(3)+3,(15)+5,55= \frac{45}{100} + \frac{21}{9} + \frac{312}{99} + \frac{555}{100} = \\ \\ = \frac{9}{20} + \frac{7}{3} + \frac{104}{33} + \frac{111}{20} = \frac{297}{660} + \frac{1540}{660} + \frac{2080}{660} + \frac{3663}{660} = \frac{7580}{660} = \frac{758}{66} = \frac{379}{33}$