Question

Efectuati:
a)[1/3+0,(3)]×9/4;
b)[1,(4)-0,(2)]:11-1/9;
c)2,5+[1,2+0,(6)]×3/7;
d)[1,(6)+2/3]×0,2+5/6;
e)[1,(24)-0,(03)]×11/20;
f)16/9:[2,(3)-0,(5)];
g)2×[2,(7)+2(intregi)1/3]-5(intregi)1/9;
h)[2×1,(3)-0,1(5)]×45/113;
i)5×[1,(2)-1,2]-0,(1);
j)25/3[0,(6)-0,0(6)]-5;
Va rog frumos!

Answer 1

a)[1/3+0,(3)]×9/4 = (1/3 + 1/3) x 9/4 = 2/3 x 9/4 = 18/12 = 3/2

b)[1,(4)-0,(2)]:11-1/9 = (13/9 - 2/9) : 11 -1/9 = 11/9 : 11 -1/9=1/9-1/9=0

c)2,5+[1,2+0,(6)]×3/7=25/10+(12/10+6/9)x3/7 = 5/2 + 168/90 x 3/7 = 5/2 + 4/5 = 33/10

d)[1,(6)+2/3]×0,2+5/6=(15/9 + 2/3)x2/10+5/6=(5/3+2/3)x2/10+5/6=
7/3x2/10+5/6=14/30+5/6=(14+25)/30=39/30=13/10

e)[1,(24)-0,(03)]×11/20 = (123/99 -3/99)x11/20=120/99 x 11/20 = 10/9

f)16/9:[2,(3)-0,(5)]=16/9:(21/9-5/9)=16/9 : 16/9=1

g)2×[2,(7)+2(intregi)1/3]-5(intregi)1/9 = 2x(25/9+7/3)-46/9=
2x46/9 - 46/9 = 92/9-46/9=46/9

h)[2×1,(3)-0,1(5)]×45/113=(2x12/9 - 15/90)x45/113 = (24/9 - 15/90)x45/113= 15/6 x 45/113 = 675/678

i)5×[1,(2)-1,2]-0,(1)= 5x(11/9-12/10)-1/9=5x1/45 - 1/9 = 1/9 - 1/9 = 0

j)25/3[0,(6)-0,0(6)]-5 = 25/3(6/9 - 6/90)-5 = 25/3 x 3/5 - 5 = 5-5=0