Question

efectuati:
a) 11x(48x3,4)+5[19+4x(8,3-5,40]-20,3
b) { 3+0,5x[2,3-0,2x(3,1-5,12:3,20]} va roggg frumos

Answer 1

11x(48x3,4)+5[19+4x(8,3-5,40)]-20,3=
11x(48x3,4)+5[19+4x2,9]-20,3=
11x(48x3,4)+5x[19+11,6]-20,3=
11x(48x3,4)+5x30,6-20,3=
11x163,2+153-20,3=
1795,2+153-20,3=
1948,2-20,3=
1927,9

{3+0,5x[2,3-0,2x(3,1-5,12:3,20)]}=
{3+0,5x[2,3-0,2x(3,1-1,6)]}=
{3+0,5x[2,3-0,2x1,5]}=
{3+0,5x[2,3-0,3]}=
{3+0,5x2}=
{3+1}=
4