Matematică, întrebare adresată de Utilizator anonim, 8 ani în urmă

Efectuati: a) 12 supra 17 * [( 1 - 1 supra 4 ) * 1 supra 5 + ( 1 - 1 supra 5 ) * 1 supra 6 ] b) [( 5 supra 9 - 17 supra4 / 51 supra 2 ) * 3 supra 8 + 1 supra 6 ] / 15 supra 16= c) 5 * [ 9 supra 10 - 1 supra 13 * ( 25 - 12 - 17 supra 20 - 12 supra 15 )]= d) [ 3 supra 10 - ( 1 supra 2 ) * ( 5 supra 3 - 24 supra 25 / 8 supra 5)] / 1 supra 6= VA ROG AJUTATI MA E URGENTTTTTTT DAU CROANA DAU ORICEEEE

Răspunsuri la întrebare

Răspuns de gabriellaaaa21
8

12/17×[(1-1/4)×1/5+(1-1/5)×1/6]=

=12/17×[(4/4-1/4)×1/5+(5/5-1/5)×1/6]

=12/17×(3/4×1/5+4/5×1/6)

=12/17×(3/20+2/15)

=12/17×(45/300+40/300)

=12/17×85/300

=1/17×85/25

=1×5/25

=1×1/5

=1/5

[(5/9-17/4 / 51/2)×3/8+1/6]/ 15/16=

[(5/9-17/4×2/51)×3/8+1/6]×16/15

[(5/9-1/2×1/3)×3/8+1/6]×16/15

[(5/9-1/6)×3/8+1/6]×16/15

[(30/54-9/54)×3/8+1/6]×16/15

(21/54×3/8+1/6)×16/15

(7/18×3/8+1/6)×16/15

(7/6×1/8+1/6)×16/15

(7/48+1/6)×16/15

(7/48+8/48)×16/15

15/48×16/15

1/48×16

16/48

1/3

5×[9/10-1/13×(25-12-17/20-12/15)]

5×[9/10-1/13×(13-17/20-12/15)]

5×[9/10-1/13×(3900/300-255/300)]

5×(9/10-1/13×3645/300)

5×(9/10-3645/3900)

5×(9×390-3645 / 3900)

5×(3510-3645 / 3900)

5×(135 / 3900)

135/780

27/156

9/52

[3/10-1/2×(5/3-24/25×5/8)]×6

[3/10-1/2×(5/3-3/5)]×6

[3/10-1/2×(25/15-9/15)]×6

(3/10-1/2×16/15)×6

(3/10-16/30)×6

(9/30-16/30)×6

-7/30×6

-7/5

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