Question

Efectuati:

a) √2·(3/√2-√2)+(3√11-5√88)÷√11=

b) (1/√5-1/√2)·√10+(1/√2+1/√5):1/√10=

c) (3√2+√3)·(√3-2√2)=

d) (√7+√2)·(√7-√2)·√2/5=

Answer 1

a) √2·(3/√2-√2)+(3√11-5√88)÷√11=
=3-2+3-5√8=
=6-10√2=
=2(3-5√2)

b) (1/√5-1/√2)·√10+(1/√2+1/√5):1/√10=
=√2-√5+√5+√2=2√2

c) (3√2+√3)·(√3-2√2)=
=3√6+3-6×2-2√6=
=√6-9

d) (√7+√2)·(√7-√2)·√2/5=
=(7-2)·√2/5=
=5·√2/5=
=√2