Question

Efectuați:
a)-2(intregi)1/4*[-1/5+1/3*(2/5-1/3)]=?
b)[0,25-0,(6)*(0,8(3)+1,5)]:3(intregi)8/13=?
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Answer 1

a) -2(intregi)1/4*[-1/5+1/3*(2/5-1/3)]=
=-9/4*[-1/5+1/3*(6-5)/15]=
=-9/4*(-1/5+1/3*1/15)=
=-9/4*(-1/5+1/45)=
=-9/4*(-9+1)/45=
=-9/4*(-8/45)=
=-1/1*(-2/5)=
=2/5
b)[0,25-0,(6)*(0,8(3)+1,5)]:3(intregi)8/13=
={1/4-6/9*[(83-8)/90+15/10)]}:47/13=
=[1/4-2/3*(75/90+3/2)]:47/13=
=[1/4-2/3*(5/6+3/2)]:47/13=
=[1/4-2/3*(5+9)/6]:47/13=
=[1/4-1/3*14/3]:47/13=
=[1/4-14/9]:47/13=
=(9-56)/36 × 13/47=
=-47/36 × 13/47=
=-13/36