Question

Efectuați : a) (4+2 la puterea 232 :2 la puterea 230) :2 la puterea 2.
B) (125+5la puterea 46:5 la puterea 33+3×5 la puterea 2):5 la puterea 2

Va roooooog ajutați ma!!!! ​

Answer 1

Răspuns:

(2^2 + 2^232:2^230):2^2=(2^2+2^2):2^2

[2^2(1+1)]:2^2

(2^2•2):2^2

2^3:2^2=2

b) (125+5^46:5^33+3•5^2):5^2=

(5^2+5^13+3•5^2):5^2=

[5^2(1+5^11+3)]:5^2=

5^11+4