Question

efectuati:
a)450+{[3×(3×41-450:15):31+2525:25]×2-9240:132}:3=

b)39+5×{2+3×[2+4×(2353-84×28)]}-7²=
c)2×{20+3×[250-7×(399-17×23)]}+215-10²=

d)49-{23+4×[25-(24:3-32:4)-20]+3}=
​

Answer 1

Răspuns:

450+{[3×(3×41-450:15):31+2525:25]×2-9240:132}:3=

450+{[3×(123-30):31+101]×2-70}:3=

450+{[3×93:31+101]×2-70}:3=

450+{[279:31+101]×2-70}:3=

450+{[9+101]×2-70}:3=

450+{110×2-70}:3=

450+{220-70}:3=

450+150:3=

450+50=

=500

39+5×{2+3×[2+4×(2353-2352)]}-49=

39+5×{2+3×[2+4×1]}-49=

39+5×{2+3×6}-49=

39+5×20-49=

39+100-49=

139-49=

=90

2×{20+3×[250-7×(399-17×23)]}+215-100=

2×{20+3×[250-7×(399-391)]}+215-100=

2×{20+3×[250-7×8]}+215-100=

2×{20+3×[250-56]}+215-100=

2×{20+3×194}+215-100=

2×{20+582}+215-100=

2×602+215-100=

1204+115=

=1319

49-{23+4×[25-(24:3-32:4)-20]+3}=

49-{23+4×[25-(8-8)-20]+3}=

49-{23+4×[25-0-20]+3}=

49-{23+4×5+3}=

49-{23+20+3}=

49-{43+3}=

49-46=

=3