Question

efectuati :
a) 5\24 - 7\32 + 11\72
\=supra

Answer 1

$\frac{5}{24}- \frac{7}{32} + \frac{11}{72}= \\ \\ \frac{5}{2^{3}*3}- \frac{7}{ 2^{3}* 2^{2}} + \frac{11}{ 2^{3}*3^{2}}= \\ \\ = \frac{5*4*3-7*9+11*4}{288} \\ \\ =\frac{60-63+44}{288} \\ \\ = \frac{41}{288}$