Question

Efectuati a) ( radical din 2 ) la puterea 6 •(1 supra 2 ) la puterea 3 - ( radical 25 supra 2 ) la puterea 6 : ( 5 supra radical din 25 ) • radical 16 supra 25 b) (1 supra 2 + radical din 3 + 2 supra radical din 3 -1) • ( 4 supra 3 radical din 2 - 3 supra 2 radical din 2)

Answer 1

2³×(1/2)³-(5/2)⁶÷5/5×4/numa5²=
(2×1/2)³-5⁶/2⁶÷1×2²/2²=
1³-5⁴/2⁴=
1-625/16=
/16-625/16=
-609/16.
b)(1/2+√3+2√3/3-1)×(4√2/6-3√2/4)=
   (1/2+/3√3+2√3/3-1)×(2√2/3-3√2/4)=
   (1/2+5√3/3-1)×(2√2/3-3√2/4)=
   (/1-2/2+5√3/3)×/8√2-9√2/12=
   (/1-2/2+5√3/3)×-√2/12=
/(-1/2+5√3/3)×(-√2)/tot supra 12=
/√2/2-5√6/3/ tot supra 12=
/3√2-10√6/tot supra 6/ si tot supra 12=
/3√2-10√2/6×12=
/3√2-10√6/72..............cam asa ceva.../bara inseamna supra....