Efectuati: a) (x-3)(x+3)(x^2+9)-(x^2+ 2)^2+ 3(x-1)^2
b) (x+5)(x^2-1)-x(x+4)^2 +(x+1)^2
c) (3xy-5)(3xy+5) - (3xy-2)^2
d) (5x-8)[2(x+1) +3(x+2)]-(3x-4)[5(x+2) -2(x+3]
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a) (x-3)(x+3)(x²+9)-(x²+ 2)²+ 3(x-1)²= (x²-9)(x²+9)-x⁴-4x²-4+3x²- 6x+3=
=x⁴- 81- x⁴-x²-6x -1 = -x² -6x-82
b) (x+5)(x²-1)-x(x+4)² +(x+1)²= x³ -x+5x²-5-x³- 8x²-16x+x²+2x+1=
= -2x²- 15x - 4
c) (3xy-5)(3xy+5) - (3xy-2)²= 9x²y² - 25 - 9x²y²+12xy- 4=12xy -29
d)(5x-8)[2(x+1) +3(x+2)]-(3x-4)[5(x+2) -2(x+3]=
=(5x-8)(5x+8)- (3x-4)(3x+4)= 25x²-64 - 9x²+16=16x²- 48
=x⁴- 81- x⁴-x²-6x -1 = -x² -6x-82
b) (x+5)(x²-1)-x(x+4)² +(x+1)²= x³ -x+5x²-5-x³- 8x²-16x+x²+2x+1=
= -2x²- 15x - 4
c) (3xy-5)(3xy+5) - (3xy-2)²= 9x²y² - 25 - 9x²y²+12xy- 4=12xy -29
d)(5x-8)[2(x+1) +3(x+2)]-(3x-4)[5(x+2) -2(x+3]=
=(5x-8)(5x+8)- (3x-4)(3x+4)= 25x²-64 - 9x²+16=16x²- 48
alyalexandra552:
multumesc:))
cu placere! :)
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