Question

Efectuați,aplicând formulele de calcul prescurtat:
a) (√3x+2)^2+(2√3-1)^2-(3√3x-√2)(3√3x+√2)
b) (3x-√5)^2+(3√5+1)^2-(2√7-√5)(2√7+5)
c) (√6+√2)^2+(√3-2x)^2-(3√2-√3x)(3√2+√3x)
d) (√5-3x)^2+(√15+√3x)^2-(3√3-√2x)(3√3+√2x)

Answer 1

a) 3x²+4√3x+4+12-4√3+1-(27x²-2) =
3x²+4√3x+19-4√3
b) 9x²-6√5x+5+45+6√5+1-(28-5) =
9x²-6√5x+28+6√5
c) 6+4√3+2+3-4√3x+4x²-(18-3x²) =
7x²-4√3x+4√3-7
d) 5-6√5x+9x²+15+2√45x+3x²-(27-2x²) = 5-6√5x+9x²+15+6√5x+3x²-27+2x² = 14x²-7 = 7(2x²-1)