Question

. Efectuați, aplicând regulile de calcul cu puteri:
a) (34.39)2 =
b) (52.58)3 =..........
c) (27. 28)3;
d) (54 . 5694; e) (72. 79); f) (62.67)

DAU COROANA !!
UITATIVA LA POZA!!

Answer 1

Răspuns:            

Explicație pas cu pas:

$\bf a)~ \big(3^4\cdot3^9\big)^2 =\big(3^{4+9}\big)^2=\big(3^{13}\big)^2=3^{13\cdot2}=\blue{\underline{3^{26}}}$

$\bf b)~ \big(5^2\cdot5^8\big)^3 =\big(5^{2+8}\big)^3=\big(5^{10}\big)^3=5^{10\cdot3}=\purple{\underline{5^{30}}}$

$\bf c)~ \big(2^7\cdot2^8\big)^3 =\big(2^{7+8}\big)^3=\big(2^{15}\big)^3=2^{15\cdot3}=\pink{\underline{2^{45}}}$

$\bf d)~ \big(5^4\cdot5^6\big)^4 =\big(5^{4+6}\big)^4=\big(5^{10}\big)^4=5^{10\cdot4}=\blue{\underline{5^{40}}}$

$\bf e)~ \big(7^2\cdot7^9\big)^6 =\big(7^{2+9}\big)^6=\big(7^{11}\big)^6=7^{11\cdot6}=\purple{\underline{7^{66}}}$

$\bf f)~ \big(6^2\cdot6^7\big)^5 =\big(6^{2+7}\big)^5=\big(6^{9}\big)^5=6^{9\cdot5}=\red{\underline{6^{45}}}$