Question

efectuați calculele: -0,(3) : (17/42 - 5/7 + 9/14) + (1/5)^-1 ​

Answer 1

Explicație pas cu pas:

$- 0.(3) = - \frac{3}{9}^{(3} = - \frac{1}{3}$

-0,(3) : (17/42 - 5/7 + 9/14) + (1/5)^-1 =

$- \frac{1}{3} \div ( \frac{17}{42} - ^{6)}\frac{5}{7} + ^{3)} \frac{9}{14} ) + (\frac{1}{5} )^{ - 1} = \\ - \frac{1}{3} \div ( \frac{17 + 30 +27 }{42}) + \frac{5}{1} =$

[tex] - \frac{1}{3} \div\frac {77}{42} + 5 = - \frac{1}{3} \times \frac{42}{77} + 5 = - \frac{1}{3} \times \frac{ 6}{11} + 5 =

- \fract{ 6}{33} + 5 = - \fract{ 2}{11} + \frac{55}{11}= \frac{57}{11}