Question

Efectuați calculele:
1) (x - 2)² + (x-3).(x + 3) =
2) (x+4)²-(2x - 5).(2x + 5) =
3) (2x - 3)²-(x - 5).(x+5)=
4) (3x-6) (3x + 6) - (4x + 1)² =
5) (2x-3).(2x + 3)-(3x - 1)² =
6) (x + 8)-(x – 8) − (5x + 3)2 =
​

Answer 1

Răspuns:

1. $x {}^{2} - 4x + 4 + x {}^{2} - 9 = 2 x{}^{2} - 5 - 4x$

$x {}^{2} + 8x + 16 - 4x {}^{2} - 25 = - 3x {}^{2} + 8x - 9$

1. $4x {}^{2} - 12x + 9 - x {}^{2} + 25 = 3x {}^{2} - 12x + 16$
2. $9x {}^{2} - 36 - 16x { }^{2} - 8x - 1 = - 7x {}^{2} - 8x - 35$
3. $4x {}^{2} - 9 - 9x {}^{2} + 6x - 1 = - 5x {}^{2} + 6x - 10$
4. $x {}^{2} - 64 - 25x {}^{2} - 30x - 9 = - 24x {}^{2} - 30x - 73$

Explicație pas cu pas:

Ceaw!S-au numerotat prost dar sunt in ordniea din exerctitiu am folosit teorema (a+b)2 si (a+b)(a-b)