Question

efectuati calculele ​

Answer 1

Răspuns:

a)

$4 - \sqrt{7} + 3 - \sqrt{7} + 2 \sqrt{7} = 7 + 0 = 7$

b)

$\sqrt{27} (8 \sqrt{3} - 6 \sqrt{3} + 5 \sqrt{3} - {3}^{2} \sqrt{3} )$

$\sqrt{27} (8 \sqrt{3} - 6 \sqrt{3} + 5 \sqrt{3} - 9 \sqrt{3} )$

$\sqrt{27} + ( - 2 \sqrt{3} )$

$- 3 \sqrt{3} \times 2 \sqrt{3} = - 3 \times 3 \times 2 = - 18$

c)

$( \frac{2 \sqrt{2} }{3} - \sqrt{ \frac{1} {5} } ) \times 3 \sqrt{6} ( \frac{2 \sqrt{3} }{3} - \frac{ \sqrt{3} }{10} ) \times \sqrt{6} - \sqrt{3} + \sqrt{2}$

$2 \sqrt{12} - 3 \sqrt{ \frac{6}{5} } - ( \frac{2 \sqrt{18} }{3} - \sqrt{ \frac{18}{10} } ) - \sqrt{3} + \sqrt{2} =$

$4 \sqrt{3} - 3 \times \frac{ \sqrt{6} }{ \sqrt{5} } - ( \frac{6 \sqrt{2} }{ 3} - \sqrt{ \frac{9}{5} } ) - \sqrt{3} + \sqrt{2} =$

$4 \sqrt{3} - \frac{ 3 \sqrt{6} }{ \sqrt{5} } - (2 \sqrt{2} - \frac{3}{ \sqrt{5} } ) - \sqrt{3} - \sqrt{2} = 4 \sqrt{3 } - \frac{3 \sqrt{30} }{5} - (2 \sqrt{2} - \frac{3 \sqrt{5} }{5} ) - \sqrt{3} + \sqrt{2} =$

$3 \sqrt{3} - \frac{3 \sqrt{30} }{5} - \sqrt{2} + \frac{3 \sqrt{5} }{5} =$

$3 \sqrt{3} + \frac{ - 3 \sqrt{30 + 3 \sqrt{5} } }{5} - \sqrt{2}$

Sper că te-am ajutat!