Question

Efectuati calculele:

Answer 1

A) (x-2)(x+2)(x²+4)-(x²+1)²+2(x+1)²

(x²-2²)(x²+4)-(x⁴+2x+1)+2(x²+2x+1)

(x²-4)(x²+4)-x⁴-2x-1+2x²+4x+2

x⁴-16-x⁴-2x-1+2x²+4x+2=2x²+2x-15

B) (x+4)(x²-3)-x(x+2)²+(x-1)²

x³-3x+4x²-12-x(x²+4x+4)+(x²-2x+1)

x³-3x+4x²-12-x³-4x³-4x+x²-2x+1

= -4x³+5x²-9x-11

C) (x²+2)(x²-5)-x²(x+1)²+2x(x-1)²

x⁴-5x²+2x²-10-x²(x²+2x+1)+2x(x²-2x+1)

x⁴-5x²+2x-10-x⁴-2x³-x²+2x³-4x²+2x

= -5x²-5x²+4x-10

= -10x²+4x-10

D) (2xy²-7)(2xy²+7)-(2xy²-1)²

4x²y⁴-49-(4x²y⁴-4xy²+1)

4x²y⁴-49-4x²y⁴+4xy-1=4xy-50

E) (5x-7)·[2(x+2)+3(x+1)]-(4x-3)·[3(x+3)+x-6]

(5x-7)(2x+4+3x+3)-(4x-3)(3x+3+x-6)

(5x-7)(5x+7)-(4x-3)(4x-3)

25x²-49-(16x²-12x-12x+9)

25x²-49-16x²+12x+12x-9=9x²+24x-58

F) (x+1)·[5(x+1)-2(x+4)]-(3x+2)·[7(x+2)-4(x+3)]

(x+1)·(5x+5-2x-8)-(3x+2)(7x+14-4x-12)

(x+1)(3x-3)-(3x+2)(3x+2)

3x²-3x+3x-3-(9x²+6x+6x+4)

3x²-3x+3x-3-9x²-6x-6x-2= -6x²-12x-5

Sper să nu fi greșit pe undeva. Te uiți la sfârșitul culegerii,dacă are răspunsuri, și verifici dacă este bine.