Question

Efectuati calculele:
a)3^2+13^0-1^10+4^2
b) 11^2-11^1+11^0
c) 5^2-2^5+19^0
d) 0^13+13^1+13^0
e) (23-3^2-23^0)^2-13^2

2. Efectuati:
f) 19-2^2×[4×9÷(3×2^2]
g)(3^2-2^3)÷(6^2-7×5)
h) (4^3-23^0)÷3^2+2^2×8
i) (2^2-3)^100+5:[3^2-4×(3^1-3^0)]×1^2013
j) 21^2-2×{11^2+21÷(2-1)+2×[1+2^3×(1+2)+2^4-2^1]}

DAU COROANA

Answer 1

a) 9+1-1+16=25
b) 121-11+1=111
c) 25-32+1=-6
d) 0+13+1=14
e) (23-9-1)^2-169=
=169-169=0
f) 19-4*(36÷12)=
=19-4*3=
=19-12=
=7
g) (9-8)÷(36-35)=
=1÷1=
=1
h)(64-1)÷9+4*8=
=63÷9+32=
=7+32=
=39
i) (4-3)^100+5÷[9-4*(3-1)*1]=
=1^100+5÷(9-8)=
=1+5=
=6
j) 441-2*[121+21÷1+2*(1+8*3+8-2)]=
=441-2*(121+21+2*31)=
=441-2*204=
=33