Question

Efectuați calculele:
a) 3^2+13^0-1^10+4^2=
b)11^2-11^1+11^0
c)5^2-2^5+19^0
d)0^13+13^1+13^0
e)(23-3^2-23^0)^2-13^2
f)(34:17)^2-2013^0
(^=la puterea)
Va rog am nevoie urgent!! ​

Answer 1

Explicație pas cu pas:

ღSalutare!ღ

a)3²+13⁰-1¹⁰+4²=9+1-1+16=10-1+16=9+16=25

b)11²-11¹+11⁰=121-11+1=110+1=111

c)5²-2⁵+19⁰=25-32+1=-7+1=-6

d)0¹³+13¹+13⁰=0+13+1=13+1=13

e) (23-3²-23⁰)²-13²=(23-9-1)²-169=(14-1)²-169=13²-169=169-169=0

f) (34:17)²-2013⁰=2²-1=4-1=3

Succes!;)