Question

Efectuați calculele:
a)a/a+b + b/a+b,a+b≠0
b)a/a+b+c +b/a+b+c +c/a+b+c,a+b+c≠0​

Answer 1

Răspuns:

Explicație pas cu pas:

So tiny!

$a) \dfrac{a}{a+b} + \dfrac{b}{a+b} = \dfrac{a+b}{a+b} = \boxed{1}\\b)\dfrac{a}{a+b+c}+\dfrac{b}{a+b+c}+\dfrac{c}{a+b+c} = \dfrac{a+b+c}{a+b+c} = 1$