Question

Efectuati calculele :
a) (x + 2 )(x^2-x+3)-(x+1)(x^2+2x-5)
b) (2x+1)(x^2-2x+4)-(x-3)(2x^2+x+3)
c)(x-3)(x^2-3x+2)-(x+3)(x^2-2x+3)
d)(2x-1)(-x^2+x-2)+(2x-3)(x^2-x+1)

Answer 1

Răspuns:

Explicație pas cu pas:

Efectuati calculele :

a) (x + 2 )(x^2-x+3)-(x+1)(x^2+2x-5)=x³-x²+3x+2x²-2x+6-x³-2x²+5x-x²-2x+5=

x³-x³-x²+2x²-2x²-x²+3x-2x+5x-2x+6+5=-2x²+4x+11

b) (2x+1)(x^2-2x+4)-(x-3)(2x^2+x+3)=                        

2x³-4x²+8x+x²-2x+4-2x³-x²-3x+6x²+3x+9=2x²+6x+13

c) (x-3)(x^2-3x+2)-(x+3)(x^2-2x+3)=  

x³-3x²+2x-3x²+9x-6-x³+2x²-3x-3x²+6x-9=-7x²+14x-15      

d) (2x-1)(-x^2+x-2)+(2x-3)(x^2-x+1)=                      

-2x³+2x²-4x+x²-x+2+2x³-2x²+2x-3x²+3x-3=-2x²-1