Question

Efectuati calculele,rationalizand numitorii : 
 5 pe √6 -1 + 3 pe 3+√6 + 7pe√11-2 + 14pe 5+√11

Answer 1

5/√6-1  rationalizam cu √6+1  si obtinem
5(√6+1)/(√6-1)(√6+1)=  5(√6+1)=6-1  =5(√6+1)/5=√6+1

3/3+√6  rationalizam cu 3-√6=3(3-√6)/9-6=   3(3-√6)/3=3-√6

7/√11-2  rationalizam cu √11+2   7(√11+2)/11-4 =  7(√11+2)/7= √11+2

14/5+√11 rationalizam cu 5-√11   14(5-√11)/25-11= 14(5-√11)/14=5-√11

√6+1+3-√6+√11+2+5-√11  se simplifica radicalii
1+3+2+5=11