Question

Efectuati calculele si scrieti rezultatul ca fractie ireductibila:a)3,(4)+0,(81):b)(0,3+2pe5)+(5-2 1pe5):c)(5pe6+1 1pe8-3pe16) inmultit cu 24pe17

Answer 1

a). 3,(4) + 0,(81) = (34-3)/9 + 81/99 = 31/9 + 81/99 = (341 + 81) / 99 = 422 / 99.

b). 2 intregi si 1/5 = 11/5:
(0,3 + 2/5) + (5 - 11/5) = 3/10 + 2/5 + 5 - 11/5 = (3 + 50 -18) / 10 = 35/10 = 7/2.

c). 1 intreg si 1/8 = 9/8:
(5/6 + 9/8 - 3/16) * 24/17 = (40+54-9)/48 * 24/17 = 85 / 2*17 = 5/2.