Question

Efectuați calculele.Va rog ajutati.ma ​

Answer 1

Răspuns:

a) $\frac{-9-5}{9}=\frac{-14}{9}$ = 1, (5)

b) $\frac{7*7-5*2}{14} = \frac{49-10}{14} =\frac{39}{14}$

c) $\frac{-4*5+1}{5} +\frac{4*15+1}{15}$= $\frac{-21}{5} +\frac{61}{15}$= $\frac{-63+61}{15}$= $\frac{-2}{15}$

d) $\frac{5*2-7*3-4*1}{36}$= $\frac{10-21-4}{36}$= $\frac{-15}{36}$= $\frac{-5}{12}$

e) $\frac{-1*12-3*6-7*4+19*3}{60}$= $\frac{-12-18-28+57}{60}$$=\frac{-58+57}{60}$= $\frac{-1}{60}$

f) $\frac{(-1)*12+7}{12}$ + ($\frac{-5*3 -7}{24}$)= $\frac{-5}{12}$ + $\frac{-15-7}{24}$= $\frac{-5}{12}$ +$\frac{-22}{24}$ = $\frac{-5}{12}$ + $\frac{-11}{12}$= $\frac{-5-11}{12}$= $\frac{-17}{12}$

g)$-\frac{8}{5} + \frac{3}{10}$ - $\frac{6}{5}$ + $\frac{103-10}{90}$= $\frac{-8*2+3-6*2}{10}$ + $\frac{31}{30}$= $\frac{-16+3-12}{10}$ +$\frac{31}{30}$=$\frac{-25}{10}$ + $\frac{31}{30}$=

$\frac{-25*3 +31}{30}$= $\frac{-44}{30}$ = $\frac{-22}{15}$

h) $\frac{42}{10}$ - $\frac{4*9+1}{9}$ - $\frac{3*6+5}{6}$ + $\frac{100}{27}$= $\frac{21}{5}$ - $\frac{37}{9}$ - $\frac{35}{6}$ +$\frac{100}{27}$= $\frac{21*27*2- 15*37*2-15*35*3+100*2*5 }{5*2*27}$=

$\frac{1134- 1110- 1575+ 1000}{270}$= $\frac{-551}{270}$

i) $\frac{-1*6-5*3-5*3-7}{18}$= $\frac{-6-15-15-7}{18}$= $\frac{-43}{18}$