Question

Efectuati calculul din imagine .. cel de jos .. care incepe cu 1 supra ..

Answer 1

$\frac{1}{3 \sqrt{2} +4} - ( \frac{1}{\sqrt{2}}- \frac{1}{2})* \frac{ \sqrt{18} }{ \sqrt{2}-1 } +3= \\ = \frac{1}{3 \sqrt{2} +4} - \frac{ \sqrt{2}-1 }{2}* \frac{3 \sqrt{2} }{\sqrt{2}-1 } +3 \\ =\frac{1}{3 \sqrt{2} +4} - \frac{3 \sqrt{2}}{2}+3 \\ = \frac{ 3\sqrt{2}-4 }{18-16} - \frac{3 \sqrt{2}}{2}+3 \\ =\frac{ 3\sqrt{2}-4 }{2} - \frac{3 \sqrt{2}}{2}+3 \\ = \frac{3 \sqrt{2}-4-3 \sqrt{2} }{2}+3 \\ = \frac{-4}{2}+3 \\ =-2+3=1$