Question

efectuati ex 7 dau corona plus 100

Answer 1

a) $0,3^{6}$ : ( $\frac{3}{5}$ ) la puterea a cincea ·$\frac{3}{10}$=( $\frac{3}{10}$ ) la puterea a 6 :( $\frac{3}{10}$ ) la puterea a 5 · $\frac{3}{10}$ =$\frac{9}{100}$

b) $0,5^{2}$ : $(-\frac{1}{4} ) *( \frac{2}{3} ){2}$ = $-\frac{1}{4} : \frac{1}{4} *\frac{4}{9}$ = -1 $*\frac{4}{9}$ = $-\frac{4}{9}$