Question

Efectuati:

f) 19 -2^2 x [4 x 9: (3x2^2)]
g) (3^2 - 2^3) : (6^2 - 7x5)
h) (4^3 - 23^0) : 3^2 + 2^2 x 8
i) (2^2 - 3)^100 +5:[3^2 = 4(3^1 = 3^0)] x 1^2013
j) 21^2 - 2x{11^2 +21:(2 - 1) + 2 x [1+2^3 x (1+2) +2^4 - 2^1]}

Answer 1

Răspuns:

f)7

g)1

h)39

j)1

Explicație pas cu pas:

f)

19-2²×[4×9:(3×2²)]=

19-4×[4×9:(3×4)]=

19-4×(4×9:12)=

19-4×(36:12)=

19-4×3=

19-12=7

g)

(3²-2³):(6²-7×5)=

(9-8):(36-35)=

1:1=1

h)

(4³-23⁰):3²+2²×8=

(64-1):9+4×8=

63:9+32=

7+32=39

i)(2²-3)¹⁰⁰+5:[3²

j)

21²-2×{11²+21:(2-1)+2×[1+2³×(1+2)+2⁴-2¹]}=

441-2×[121+21:1+2×(1+8×3+16-2)]=

441-2×[121+21+2×(1+24+16-2)]=

441-2×[121+21+2×(25+16-2)]=

441-2×[121+21+2×(41-2)]=

441-2×(121+21+2×39)=

441-2×(121+21+78)=

441-2×(142+78)=

441-2×220=

441-440=1

sper că te-am ajutat