Question

Efectuati folosind formulele de calcul prescurtatL:
(radical 2+x)patrat 2, (x-radical5)patrat 2

Answer 1

$( \sqrt{2 } + x ) {}^{2} = \sqrt{2} {}^{2} + 2 \sqrt{2} x + x {}^{2} = 2 + 2 \sqrt{2} x + x {}^{2}$

$( \sqrt{x - \sqrt{5} } ) {}^{2} = \sqrt{x} {}^{2} - 2 \sqrt{x} \times 5 + 5 {}^{2} = x - 10 \sqrt{x} + 25$