Question

Efectuati, respectând ordinea efectuării operațiilor
(x+2)^+2(2x-3)(2x+3)-(3x-2)^2

Answer 1

$(x+2)^2+2(2x-3)(2x+3)-(3x-2)^2=\ \textgreater \ \\ x^{2} +4x+4+2(4 x^{2} -9)-(9 x^{2} -12x+4)=\ \textgreater \ \\ x^{2} +4x+4+8 x^{2} -18-9 x^{2} +12x-4=\ \textgreater \ \\ 0+16x-18=\ \textgreater \ \\ 16x-18 \\ Succes$