Question

efectuati respectand ordinea operatiilor:
a) 4*[27+11*(804-29*13)]-32*18
b)[(79*8-26)*5+3*(473-11*42)]*10-9*21

Answer 1

a)4×[27+11×(804-29×13)]-32×18=
4×[27+11×(807-377)]-32×18=
4×[27+11×430]-32×18=
4×[27+4730]-32×18=
4×4757-32×18=
19028-576=
18452
b)[(79×8-26)×5+3×(473-11×42)]×10-9×21=
[(632-26)×5+3×(473-462)]×10-9×21=
[606×5+3×411]×10-9×21=
[3030+1233]×10-9×21=
4253×10-9×21=
42530-189=
42341