Question

efectuati si apoi simplificati fractiile rezultate pana obtineti o fractie ireductibila a) 4/21+24/21 b) 47/14-19/14 c) 7/2 +6/4 ajutati ma pana la 20:00

Answer 1

$a) \frac{4}{21} + \frac{24}{21} = \frac{4 + 24}{21} = { \frac{28}{21} }^{(7} = \frac{4}{3} = 1 \frac{1}{3}$

$b) \frac{47}{14} - \frac{19}{14} = \frac{47 - 19}{14} = \frac{28}{14} = 2$

$c) \frac{7}{2} + \frac{6}{4} = \frac{7 \times 2}{2 \times 2} + \frac{6}{4} = \frac{14}{4} + \frac{6}{4} = \frac{14 + 6}{4} = \frac{20}{4} = 5$

Answer 2

Răspuns:

atat

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