Question

Efectuati:
$(3^{200}+3^{203}):(3^{200}-3^{199}+3^{198})$

Answer 1

$3^{200}(1+3^3):3^{198}(3^2-3+1)= \\ = \frac{3^{200}(1+3^3)}{3^{198}(3^2-3+1)} = \\ = \frac{3^2*28}{7} = 3^2*4=9*4=36$