Question

Efectuati :
$( \frac{1}{ \sqrt{8} } + \frac{1}{ \sqrt{32} } - \frac{1}{ \sqrt{2} }) : \frac{ \sqrt{2} }{2}$

Answer 1

$=( \frac{1}{2 \sqrt{2} } + \frac{1}{4 \sqrt{2} }- \frac{1}{ \sqrt{2} })* \frac{2}{ \sqrt{2} }= \\ =( \frac{1}{2 \sqrt{2} } + \frac{1}{4 \sqrt{2} }- \frac{1}{ \sqrt{2} } )* \sqrt{2}= \\ = \frac{1}{2}+ \frac{1}{4}-1= \\ = \frac{2}{4}+ \frac{1}{4}- \frac{4}{4}= \\ = -\frac{1}{4}$

Answer 2

=(1/2√2+1/4√2-1/√2)x2/√2
=[(2+1-4)/4√2)]x2/√2
=(-1/4√2)x2/√2 simplificam cu 2
=(-1/2√2)x1/√2
=-1/4