Question

Efectuati,utilizand factorul comun
A ) 3*5 la puterea 47+2*5 la puterea 48+6*5 la puterea 49=

B)9 la p.1001+9 la p.1000+7*9 la puterea 999=

C) 7*4 la p.35+2*4 la p.36-4 la p.34=

D)13 la p.14 *3-13 la puterea 13*2-13 la puterea 12=

E)8 la p.200-3*8 la puterea 198+3*8 la puterea 197 =

P-inseamna prescurtat ''puterea''
*-Inmultit (cei care nu stiu)
Va rog frumos,sa ma ajutati la acest exercitiu! :* Multuuumesc <3

Answer 1

A ) 3x5^47+2x5^48+6x5^49=
=5^47(3+2x5+6x5^2)=
=5^47(3+10+150)=5^47x153=5^47x3^2x17

B)9^1001+9^1000+7x9^999=
=9^999(9^2+9+7)=
=9^999(81+9+7)=
=9^999 x97

 C) 7x4^35+2x4^36-4^34=
=4^34(7x4+2x4^2-1)=
=4^34(28+32-1)=
=4^34 x59

D)(13^14) x3-(13^13)x2-13^12=
=13^12(13^2 x3-13^1x2-1)=
=13^12(507-26-1)=
=13^2 x 480= 13^2 x 2^5 x 3x5



E)8^200-3*8^198+3*8^197 =
=8^197(8^3-3*8+3) =
=8^197(512-24+3)=
=8^197 x 491