Question

efectuati: (x+3)·(x-3)+(x+3)²-(√2x-1)²

Answer 1

(x+3)·(x-3)+(x+3)²-(√2x-1)² =
=x²-9+x²+6x+9-2x²+2√2x-1=
=6x+2√2x-1


(x+3)·(x-3)+(x+3)²-(√2x-1)² =0
x²-9+x²+6x+9-2x²+2√2x-1=0
6x+2√2x-1=0
x(6+2√2)=1
x=1/(6+2√2)
x=(6-2√2)/(6+2√2)(6-2√2)
x=(6-2√2)/(36-8)
x=(6-2√2)/24
x=(3-√2)/12

Answer 2

-2x+1+(x+3)la puterea 2 +x laputerea 2 -x*3+3x-9           2)(operatie) xla puterea2 + x la puterea a 2  +2x*3+3 la puterea 2 -2x-8 3)(operatie) 9+2x la puterea 2+6x-2x-8 egal cu 2x la puterea2 +4x-1