Question

efectuati x la a 2 -9 supra y la a 3 -y :xla a 2 -6x +9 supra 4yla a 2 -4

Answer 1

$\frac{(x-3)(x+3)}{y( y^{2} -1)} * \frac{4( y^{2} -1)}{ (x+3)^{2} } = \frac{4(x-3)}{y(x+3)}$