Question

efectueaza: a)80-75:(3+12)+2x101; b) 76+2x[405-816:(11-7)]-21:21; c) (100-82)x3+[(405-305)x(72:9)]:(208-188).

Answer 1

a)80-75÷(3+12)+2×101=80-75÷15+2×101=80-5+202=75+202=277

b)76+2×[405-816÷(11-7)]-21÷21= 76+2×(405-816÷4)-21÷21=76+2×(405-204)-21÷21=76+2×201-21÷21=76+402-1=478-1=477 c)(100-82)×3+[(405-305)×(72÷9)]÷(208-188)=18×3+(100×8)÷20=18×3+800÷20=54+40=94

Answer 2

a)80-75:(3+12)+2×101=

80-75:15+202=

80-5+202=

75+202=277

b)76+2×[405-816:(11-7)]-21:21=

76+2×(405-816:4)-1=

76+2×(405-204)-1=

76+2×201-1=

76+402-1=

478-1=477

c)(100-82)×3+[(405-305)×(72:9)]:(208-188)=

8×3+(105×8):20=

24+840:20=

25+42=67