Question

Efectueaza f): 0^1+1^0+2^3+4^5+5^4-349=

Answer 1

f)0+1+8+768+625-349=1053

${0}^{1} = 0 \\ {1}^{0} = 1 \\ {2}^{3} = 8 \\ {4}^{5} = 768 \\ {5}^{4} = 625$

Answer 2

1)calculăm puterile.
0^1=0
1^0=1
2^3=8
4^5=1024
5^4=625
1+8+1024+625-349=
1658-349=
1309