Question

efectueaza folosind factorul comun(a+b)×(b+c)×(c+a)-(a+b)×(b-c)×(a+c)​

Answer 1

Răspuns:

(a+b)·(b+c)·(c+a) - (a+b)·(b-c)·(a+c)​=

(a+b)(a+c)[(b+c)-(b-c)]=

(a+b)(a+c)(b+c-b+c)=

(a+b)(a+c)·2c

Answer 2

$\it (a+b) \cdot (b+c) \cdot (c+a)\ -\ (a+b) \cdot (b-c) \cdot (a+c)=(a+b)(a+c)(b+c-b+c)=\\ \\ =(a+b)(a+c)\cdot2c=2c(a+b)(a+c)$