Question

Efectuează în două moduri:
5 x (5 + 2)
(3 + 2 + 4) x 10
8 x (6-3)
(5 +1 +2) X9
(2 + 4) 9
8 (7-3)
(5 - 3) x 6
10 × (4+3 - 2)​

Answer 1

Răspuns:

primul mod :

5×(5+2)=

5×7=35

(3+2+4)×10=

9×10=90

8×(6-3)=

8×3=24

(5+1+2)×9=

8×9=72

(2+4)×9=

6×9=54

8×(7-3)=

8×4=32

(5-3)×6=

2×6=12

10×(4+3-2)=

10×5=50

Al 2-lea mod :

1:5×5+5×2=25+10=35

2:10×3+10×2+10×4=30+20+40=90

3:8×6-8×3=48-24=24

4:9×5+9×2+9×1=45+18+9=72

5:9×2+9×4=18+36=54

6:8×7-8×3=56-24=32

7:6×5-6×3=35-18=12

8:10×4+10×3-10×2=40+30-20=70-20=50