Question

Efectuează prin doua moduri 4x(6+2)=, 5x(9+1)=, 3x(1+2+4)=, 9x(2+3+4)=, (1+6+2)x7=​

Answer 1

Răspuns:

Explicație pas cu pas:

4x(6+2)=4x8=32

4x6+4x2=24+8=32

5x(9+1)=5x10=50

5x9+5x1=45+5=50

3x(1+2+4)=3x7=21

3x1+3x2+3x4=3+6+12=21

9x(2+3+4)=9x9=81

9x2+9x3+9x4=18+27+36=81

(1+6+2)x7=9x7=63

1x7+6x7+2x7=7+42+14=63

Answer 2

4×(6+2)= 4×8=32

(4×6)+(4×2)=24+8=32

5×(9+1)= 5×10=50

(5×9)+(5×1)= 45+5=50

3×(1+2+4)=3×7=21

(3×1)+(3×2)+(3×4)= 3+6+12=21

9×(2+3+4)=9×9=81

(9×2)+(9×3)+(9×4)= 18+27+36=81

(1+6+2)×7=9×7=63

(1×7)+(6×7)+(2×7)=7+42+14=63